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4x^2=0.16x
We move all terms to the left:
4x^2-(0.16x)=0
We add all the numbers together, and all the variables
4x^2-(+0.16x)=0
We get rid of parentheses
4x^2-0.16x=0
a = 4; b = -0.16; c = 0;
Δ = b2-4ac
Δ = -0.162-4·4·0
Δ = 0.0256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.16)-\sqrt{0.0256}}{2*4}=\frac{0.16-\sqrt{0.0256}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.16)+\sqrt{0.0256}}{2*4}=\frac{0.16+\sqrt{0.0256}}{8} $
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